Differentiating Powers of x (DP IB Applications & Interpretation (AI)): Revision Note

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Differentiating Powers of x

What is differentiation?

  • Differentiation is the process of finding an expression of the derivative (gradient function) from the expression of a function

How do I differentiate powers of x?

  • Powers of x are differentiated according to the following formula:

    • Ifspace f left parenthesis x right parenthesis equals x to the power of n thenspace f apostrophe left parenthesis x right parenthesis equals n x to the power of n minus 1 end exponent where n element of straight rational numbers

    • This is given in the formula booklet

  • If the power of x is multiplied by a constant then the derivative is also multiplied by that constant

    • Ifspace f left parenthesis x right parenthesis equals a x to the power of n thenspace f apostrophe left parenthesis x right parenthesis equals a n x to the power of n minus 1 end exponent where n element of straight rational numbers and a is a constant

  • The alternative notation (tospace f apostrophe left parenthesis x right parenthesis) is to use fraction numerator straight d y over denominator straight d x end fraction

    • If y equals a x to the power of n then fraction numerator straight d y over denominator straight d x end fraction equals a n x to the power of n minus 1 end exponent

      • e.g.  If y equals negative 4 x to the power of 1 half end exponent then fraction numerator straight d y over denominator straight d x end fraction equals negative 4 cross times 1 half cross times x to the power of 1 half minus 1 end exponent equals negative 2 x to the power of negative 1 half end exponent

  • Don't forget these two special cases:

    • Ifspace f left parenthesis x right parenthesis equals a x thenspace f apostrophe left parenthesis x right parenthesis equals a

      • e.g.  If y equals 6 x then fraction numerator straight d y over denominator straight d x end fraction equals 6

    • Ifspace f left parenthesis x right parenthesis equals a thenspace f apostrophe left parenthesis x right parenthesis equals 0

      • e.g.  If y equals 5 then fraction numerator straight d y over denominator straight d x end fraction equals 0

    • These allow you to differentiate linear terms in x and constants

  • Functions involving roots will need to be rewritten as fractional powers of x first

    • e.g.  If space f left parenthesis x right parenthesis equals 2 square root of x then rewrite asspace f left parenthesis x right parenthesis equals 2 x to the power of 1 half end exponent and differentiate

  • Functions involving fractions with denominators in terms of x will need to be rewritten as negative powers of x first

    • e.g.  Ifspace f left parenthesis x right parenthesis equals 4 over x then rewrite asspace f left parenthesis x right parenthesis equals 4 x to the power of negative 1 end exponent and differentiate

How do I differentiate sums and differences of powers of x?

  •  The formulae for differentiating powers of x apply to all rational powers so it is possible to differentiate any expression that is a sum or difference of powers of x

    • e.g.  Ifspace f left parenthesis x right parenthesis equals 5 x to the power of 4 minus 3 x to the power of 2 over 3 end exponent plus 4 then
      space f apostrophe left parenthesis x right parenthesis equals 5 cross times 4 x to the power of 4 minus 1 end exponent minus 3 cross times 2 over 3 x to the power of 2 over 3 minus 1 end exponent plus 0
      space f apostrophe left parenthesis x right parenthesis equals 20 x cubed minus 2 x to the power of negative 1 third end exponent

  • Products and quotients cannot be differentiated in this way so would need expanding/simplifying first

    • e.g.  Ifspace f left parenthesis x right parenthesis equals left parenthesis 2 x minus 3 right parenthesis left parenthesis x squared minus 4 right parenthesis then expand tospace f left parenthesis x right parenthesis equals 2 x cubed minus 3 x squared minus 8 x plus 12 which is a sum/difference of powers of x and can be differentiated

Examiner Tips and Tricks

  • A common mistake is not simplifying expressions before differentiating

    • The derivative of open parentheses x squared plus 3 close parentheses open parentheses x cubed minus 2 x plus 1 close parentheses can not be found by multiplying the derivatives of open parentheses x squared plus 3 close parentheses and open parentheses x cubed minus 2 x plus 1 close parentheses

Worked Example

The functionspace f left parenthesis x right parenthesis is given by

space f left parenthesis x right parenthesis equals 2 x cubed plus fraction numerator 4 over denominator square root of x end fraction,  where x greater than 0

Find the derivative ofspace f left parenthesis x right parenthesis

5-1-1-ib-sl-ai-aa-extra-we2-soltn-a

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Paul

Author: Paul

Expertise: Maths Content Creator

Paul has taught mathematics for 20 years and has been an examiner for Edexcel for over a decade. GCSE, A level, pure, mechanics, statistics, discrete – if it’s in a Maths exam, Paul will know about it. Paul is a passionate fan of clear and colourful notes with fascinating diagrams.

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